memcpy - copy bytes in memory
#include <string.h>
void *memcpy(void *s1, const void *s2, size_t n);
The memcpy() function copies n bytes from the object pointed to by s2 into the object pointed to by s1. If copying takes place between objects that overlap, the behaviour is undefined.
The memcpy() function returns s1; no return value is reserved to indicate an error.
No errors are defined.
None.
The memcpy() function does not check for the overflowing of the receiving memory area.
None.
<string.h>.